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313503404305307 is a prime number
BaseRepresentation
bin100011101001000010011001…
…1000011001010101110011011
31112010000122002021110110022212
41013102010303003022232123
5312042414433000232212
63030433250430105335
7123014605420316366
oct10722046303125633
91463018067413285
10313503404305307
119098a057793677
122b1b308794b24b
13105c13235b0628
14575b907c4d0dd
152639e22931e22
hex11d21330cab9b

313503404305307 has 2 divisors, whose sum is σ = 313503404305308. Its totient is φ = 313503404305306.

The previous prime is 313503404305271. The next prime is 313503404305327. The reversal of 313503404305307 is 703503404305313.

It is a strong prime.

It is an emirp because it is prime and its reverse (703503404305313) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 313503404305307 - 210 = 313503404304283 is a prime.

It is a super-2 number, since 2×3135034043053072 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (313503404305327) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156751702152653 + 156751702152654.

It is an arithmetic number, because the mean of its divisors is an integer number (156751702152654).

Almost surely, 2313503404305307 is an apocalyptic number.

313503404305307 is a deficient number, since it is larger than the sum of its proper divisors (1).

313503404305307 is an equidigital number, since it uses as much as digits as its factorization.

313503404305307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 680400, while the sum is 41.

The spelling of 313503404305307 in words is "three hundred thirteen trillion, five hundred three billion, four hundred four million, three hundred five thousand, three hundred seven".