Base | Representation |
---|---|
bin | 1110010000011011110100… |
… | …00100001001001011101111 |
3 | 11010000010110002021002020211 |
4 | 13020031322010021023233 |
5 | 13102123334113400142 |
6 | 150402242422123251 |
7 | 6414015233536033 |
oct | 710157204111357 |
9 | 133003402232224 |
10 | 31351014200047 |
11 | 9a97988218853 |
12 | 3624053280527 |
13 | 1465507445a79 |
14 | 7a557bc2c1c3 |
15 | 3957a262c917 |
hex | 1c837a1092ef |
31351014200047 has 2 divisors, whose sum is σ = 31351014200048. Its totient is φ = 31351014200046.
The previous prime is 31351014199997. The next prime is 31351014200057. The reversal of 31351014200047 is 74000241015313.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31351014200047 - 239 = 30801258386159 is a prime.
It is a super-3 number, since 3×313510142000473 (a number of 41 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31351014199991 and 31351014200018.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31351014200057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15675507100023 + 15675507100024.
It is an arithmetic number, because the mean of its divisors is an integer number (15675507100024).
Almost surely, 231351014200047 is an apocalyptic number.
31351014200047 is a deficient number, since it is larger than the sum of its proper divisors (1).
31351014200047 is an equidigital number, since it uses as much as digits as its factorization.
31351014200047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 31.
The spelling of 31351014200047 in words is "thirty-one trillion, three hundred fifty-one billion, fourteen million, two hundred thousand, forty-seven".
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