Base | Representation |
---|---|
bin | 1110010000100001100101… |
… | …10011001010100110000111 |
3 | 11010000102110002012120121221 |
4 | 13020100302303022212013 |
5 | 13102201211031044333 |
6 | 150403514135421211 |
7 | 6414155106462055 |
oct | 710206263124607 |
9 | 133012402176557 |
10 | 31354113534343 |
11 | 9a99228765556 |
12 | 3624779224807 |
13 | 14658ac599aa2 |
14 | 7a57936d11d5 |
15 | 3958d4793d2d |
hex | 1c8432cca987 |
31354113534343 has 2 divisors, whose sum is σ = 31354113534344. Its totient is φ = 31354113534342.
The previous prime is 31354113534313. The next prime is 31354113534353. The reversal of 31354113534343 is 34343531145313.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31354113534343 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 31354113534343.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31354113534313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15677056767171 + 15677056767172.
It is an arithmetic number, because the mean of its divisors is an integer number (15677056767172).
Almost surely, 231354113534343 is an apocalyptic number.
31354113534343 is a deficient number, since it is larger than the sum of its proper divisors (1).
31354113534343 is an equidigital number, since it uses as much as digits as its factorization.
31354113534343 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1166400, while the sum is 43.
Adding to 31354113534343 its reverse (34343531145313), we get a palindrome (65697644679656).
The spelling of 31354113534343 in words is "thirty-one trillion, three hundred fifty-four billion, one hundred thirteen million, five hundred thirty-four thousand, three hundred forty-three".
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