3135423433 has 4 divisors (see below), whose sum is σ = 3135546820. Its totient is φ = 3135300048.

The previous prime is 3135423419. The next prime is 3135423437. The reversal of 3135423433 is 3343245313.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 503015184 + 2632408249 = 22428^2 + 51307^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3135423433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3135423395 and 3135423404.

It is not an unprimeable number, because it can be changed into a prime (3135423437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7998 + ... + 79591.

It is an arithmetic number, because the mean of its divisors is an integer number (783886705).

Almost surely, 2^3135423433 is an apocalyptic number.

It is an amenable number.

3135423433 is a deficient number, since it is larger than the sum of its proper divisors (123387).

3135423433 is an equidigital number, since it uses as much as digits as its factorization.

3135423433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 123386.

The product of its digits is 38880, while the sum is 31.

The square root of 3135423433 is about 55994.8518437186. The cubic root of 3135423433 is about 1463.6325746457.

Adding to 3135423433 its reverse (3343245313), we get a palindrome (6478668746).

The spelling of 3135423433 in words is "three billion, one hundred thirty-five million, four hundred twenty-three thousand, four hundred thirty-three".