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313555404263 is a prime number
BaseRepresentation
bin1001001000000010101…
…10111100010111100111
31002222100012210220121212
410210001112330113213
520114130140414023
6400013444302035
731440123650363
oct4440126742747
91088305726555
10313555404263
11110a83940142
12509290a191b
13237502b388a
14112675662a3
15825276ee78
hex49015bc5e7

313555404263 has 2 divisors, whose sum is σ = 313555404264. Its totient is φ = 313555404262.

The previous prime is 313555404241. The next prime is 313555404271. The reversal of 313555404263 is 362404555313.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 313555404263 - 214 = 313555387879 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 313555404263.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (313555404293) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156777702131 + 156777702132.

It is an arithmetic number, because the mean of its divisors is an integer number (156777702132).

Almost surely, 2313555404263 is an apocalyptic number.

313555404263 is a deficient number, since it is larger than the sum of its proper divisors (1).

313555404263 is an equidigital number, since it uses as much as digits as its factorization.

313555404263 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648000, while the sum is 41.

Adding to 313555404263 its reverse (362404555313), we get a palindrome (675959959576).

The spelling of 313555404263 in words is "three hundred thirteen billion, five hundred fifty-five million, four hundred four thousand, two hundred sixty-three".