Search a number
-
+
3139393550071 is a prime number
BaseRepresentation
bin101101101011110010011…
…011111111011011110111
3102010010022201211022021211
4231223302123333123313
5402413434222100241
610402114551022251
7442546045611562
oct55536233773367
912103281738254
103139393550071
1110004558a7029
1242852866a987
1319a07487858c
14abd39b7d4d9
15569e20c1781
hex2daf26ff6f7

3139393550071 has 2 divisors, whose sum is σ = 3139393550072. Its totient is φ = 3139393550070.

The previous prime is 3139393550057. The next prime is 3139393550107. The reversal of 3139393550071 is 1700553939313.

3139393550071 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (3139393550107) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 3139393550071 - 29 = 3139393549559 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3139393549997 and 3139393550024.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3139393550011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1569696775035 + 1569696775036.

It is an arithmetic number, because the mean of its divisors is an integer number (1569696775036).

Almost surely, 23139393550071 is an apocalyptic number.

3139393550071 is a deficient number, since it is larger than the sum of its proper divisors (1).

3139393550071 is an equidigital number, since it uses as much as digits as its factorization.

3139393550071 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1148175, while the sum is 49.

The spelling of 3139393550071 in words is "three trillion, one hundred thirty-nine billion, three hundred ninety-three million, five hundred fifty thousand, seventy-one".