Base | Representation |
---|---|
bin | 1001001000110111101… |
… | …11011100101110010011 |
3 | 1010000111012122110202222 |
4 | 10210123313130232103 |
5 | 20121033013224021 |
6 | 400125532331255 |
7 | 31454134043555 |
oct | 4443367345623 |
9 | 1100435573688 |
10 | 314000133011 |
11 | 111191986464 |
12 | 50a32013b2b |
13 | 237c1486196 |
14 | 112aa6514d5 |
15 | 827b81b6ab |
hex | 491bddcb93 |
314000133011 has 2 divisors, whose sum is σ = 314000133012. Its totient is φ = 314000133010.
The previous prime is 314000132959. The next prime is 314000133017. The reversal of 314000133011 is 110331000413.
It is a strong prime.
It is an emirp because it is prime and its reverse (110331000413) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-314000133011 is a prime.
It is a super-2 number, since 2×3140001330112 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (314000133017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157000066505 + 157000066506.
It is an arithmetic number, because the mean of its divisors is an integer number (157000066506).
Almost surely, 2314000133011 is an apocalyptic number.
314000133011 is a deficient number, since it is larger than the sum of its proper divisors (1).
314000133011 is an equidigital number, since it uses as much as digits as its factorization.
314000133011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 314000133011 its reverse (110331000413), we get a palindrome (424331133424).
The spelling of 314000133011 in words is "three hundred fourteen billion, one hundred thirty-three thousand, eleven".
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