Base | Representation |
---|---|
bin | 1110010001110111000110… |
… | …00010111100100110110011 |
3 | 11010011210221101120111001122 |
4 | 13020323203002330212303 |
5 | 13103424220123244243 |
6 | 150440545313252455 |
7 | 6420401525235011 |
oct | 710734302744663 |
9 | 133153841514048 |
10 | 31400020134323 |
11 | a006745850585 |
12 | 363164b26412b |
13 | 146a017275709 |
14 | 7a7aaa5178b1 |
15 | 396bbeab4668 |
hex | 1c8ee30bc9b3 |
31400020134323 has 2 divisors, whose sum is σ = 31400020134324. Its totient is φ = 31400020134322.
The previous prime is 31400020134319. The next prime is 31400020134433. The reversal of 31400020134323 is 32343102000413.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31400020134323 - 22 = 31400020134319 is a prime.
It is a super-2 number, since 2×314000201343232 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31400020134292 and 31400020134301.
It is not a weakly prime, because it can be changed into another prime (31400020134023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15700010067161 + 15700010067162.
It is an arithmetic number, because the mean of its divisors is an integer number (15700010067162).
Almost surely, 231400020134323 is an apocalyptic number.
31400020134323 is a deficient number, since it is larger than the sum of its proper divisors (1).
31400020134323 is an equidigital number, since it uses as much as digits as its factorization.
31400020134323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 31400020134323 its reverse (32343102000413), we get a palindrome (63743122134736).
The spelling of 31400020134323 in words is "thirty-one trillion, four hundred billion, twenty million, one hundred thirty-four thousand, three hundred twenty-three".
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