Base | Representation |
---|---|
bin | 1110010001110111000110… |
… | …00010111100101000100001 |
3 | 11010011210221101120111012201 |
4 | 13020323203002330220201 |
5 | 13103424220123300213 |
6 | 150440545313253201 |
7 | 6420401525235226 |
oct | 710734302745041 |
9 | 133153841514181 |
10 | 31400020134433 |
11 | a006745850675 |
12 | 363164b264201 |
13 | 146a017275792 |
14 | 7a7aaa51794d |
15 | 396bbeab46dd |
hex | 1c8ee30bca21 |
31400020134433 has 2 divisors, whose sum is σ = 31400020134434. Its totient is φ = 31400020134432.
The previous prime is 31400020134323. The next prime is 31400020134437. The reversal of 31400020134433 is 33443102000413.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 21003632352784 + 10396387781649 = 4582972^2 + 3224343^2 .
It is a cyclic number.
It is not a de Polignac number, because 31400020134433 - 217 = 31400020003361 is a prime.
It is a super-2 number, since 2×314000201344332 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (31400020134437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15700010067216 + 15700010067217.
It is an arithmetic number, because the mean of its divisors is an integer number (15700010067217).
Almost surely, 231400020134433 is an apocalyptic number.
It is an amenable number.
31400020134433 is a deficient number, since it is larger than the sum of its proper divisors (1).
31400020134433 is an equidigital number, since it uses as much as digits as its factorization.
31400020134433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 31400020134433 its reverse (33443102000413), we get a palindrome (64843122134846).
The spelling of 31400020134433 in words is "thirty-one trillion, four hundred billion, twenty million, one hundred thirty-four thousand, four hundred thirty-three".
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