3140011553132 has 6 divisors (see below), whose sum is σ = 5495020217988. Its totient is φ = 1570005776564.

The previous prime is 3140011553111. The next prime is 3140011553179. The reversal of 3140011553132 is 2313551100413.

It is a junction number, because it is equal to n+sod(n) for n = 3140011553095 and 3140011553104.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 392501444138 + ... + 392501444145.

It is an arithmetic number, because the mean of its divisors is an integer number (915836702998).

Almost surely, 2^{3140011553132} is an apocalyptic number.

It is an amenable number.

3140011553132 is a deficient number, since it is larger than the sum of its proper divisors (2355008664856).

3140011553132 is a wasteful number, since it uses less digits than its factorization.

3140011553132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 785002888287 (or 785002888285 counting only the distinct ones).

The product of its (nonzero) digits is 5400, while the sum is 29.

Adding to 3140011553132 its reverse (2313551100413), we get a palindrome (5453562653545).

The spelling of 3140011553132 in words is "three trillion, one hundred forty billion, eleven million, five hundred fifty-three thousand, one hundred thirty-two".