Base | Representation |
---|---|
bin | 1110010001110111101000… |
… | …11101111001011101111111 |
3 | 11010011211200202112201200221 |
4 | 13020323310131321131333 |
5 | 13103430314434141111 |
6 | 150441034314002211 |
7 | 6420412004452423 |
oct | 710736435713577 |
9 | 133154622481627 |
10 | 31400312412031 |
11 | a006885830102 |
12 | 3631711116367 |
13 | 146a06299b5c4 |
14 | 7a7ad727ab83 |
15 | 396bda59a371 |
hex | 1c8ef477977f |
31400312412031 has 2 divisors, whose sum is σ = 31400312412032. Its totient is φ = 31400312412030.
The previous prime is 31400312412023. The next prime is 31400312412059. The reversal of 31400312412031 is 13021421300413.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31400312412031 - 23 = 31400312412023 is a prime.
It is a super-2 number, since 2×314003124120312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31400312411987 and 31400312412005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31400312412331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15700156206015 + 15700156206016.
It is an arithmetic number, because the mean of its divisors is an integer number (15700156206016).
Almost surely, 231400312412031 is an apocalyptic number.
31400312412031 is a deficient number, since it is larger than the sum of its proper divisors (1).
31400312412031 is an equidigital number, since it uses as much as digits as its factorization.
31400312412031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 31400312412031 its reverse (13021421300413), we get a palindrome (44421733712444).
The spelling of 31400312412031 in words is "thirty-one trillion, four hundred billion, three hundred twelve million, four hundred twelve thousand, thirty-one".
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