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3140049023 is a prime number
BaseRepresentation
bin1011101100101001…
…0101100001111111
322002211120000110222
42323022111201333
522412323032043
61235330051555
7140545655606
oct27312254177
98084500428
103140049023
111371526341
12737719bbb
133b070ac97
1421b060a3d
15135a09d68
hexbb29587f

3140049023 has 2 divisors, whose sum is σ = 3140049024. Its totient is φ = 3140049022.

The previous prime is 3140048981. The next prime is 3140049047. The reversal of 3140049023 is 3209400413.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3140049023 - 26 = 3140048959 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3140048983 and 3140049001.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3140049323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1570024511 + 1570024512.

It is an arithmetic number, because the mean of its divisors is an integer number (1570024512).

Almost surely, 23140049023 is an apocalyptic number.

3140049023 is a deficient number, since it is larger than the sum of its proper divisors (1).

3140049023 is an equidigital number, since it uses as much as digits as its factorization.

3140049023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 26.

The square root of 3140049023 is about 56036.1403292554. The cubic root of 3140049023 is about 1464.3519711167.

Adding to 3140049023 its reverse (3209400413), we get a palindrome (6349449436).

The spelling of 3140049023 in words is "three billion, one hundred forty million, forty-nine thousand, twenty-three".