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314010140243 = 437302561401
BaseRepresentation
bin1001001000111000111…
…01100111111001010011
31010000111220110220010012
410210130131213321103
520121043043441433
6400130531025135
731454315103302
oct4443435477123
91100456426105
10314010140243
111111975a0aa8
1250a3543b1ab
13237c357b117
14112abad8439
15827c646848
hex491c767e53

314010140243 has 4 divisors (see below), whose sum is σ = 321312701688. Its totient is φ = 306707578800.

The previous prime is 314010140233. The next prime is 314010140251. The reversal of 314010140243 is 342041010413.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 314010140243 - 212 = 314010136147 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (314010140233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3651280658 + ... + 3651280743.

It is an arithmetic number, because the mean of its divisors is an integer number (80328175422).

Almost surely, 2314010140243 is an apocalyptic number.

314010140243 is a deficient number, since it is larger than the sum of its proper divisors (7302561445).

314010140243 is an equidigital number, since it uses as much as digits as its factorization.

314010140243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7302561444.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 314010140243 its reverse (342041010413), we get a palindrome (656051150656).

The spelling of 314010140243 in words is "three hundred fourteen billion, ten million, one hundred forty thousand, two hundred forty-three".

Divisors: 1 43 7302561401 314010140243