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3140110100411 = 9923316447657
BaseRepresentation
bin101101101100011101001…
…001011010011110111011
3102010012011200010211120022
4231230131021122132323
5402421421141203121
610402314025121055
7442602566313614
oct55543511323673
912105150124508
103140110100411
11100079331a999
124286a862918b
1319a15a160b6b
14abda6dc4c0b
1556a34e62aab
hex2db1d25a7bb

3140110100411 has 4 divisors (see below), whose sum is σ = 3140426557992. Its totient is φ = 3139793642832.

The previous prime is 3140110100381. The next prime is 3140110100419. The reversal of 3140110100411 is 1140010110413.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3140110100411 - 210 = 3140110099387 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 3140110100411.

It is not an unprimeable number, because it can be changed into a prime (3140110100419) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 158213906 + ... + 158233751.

It is an arithmetic number, because the mean of its divisors is an integer number (785106639498).

Almost surely, 23140110100411 is an apocalyptic number.

3140110100411 is a deficient number, since it is larger than the sum of its proper divisors (316457581).

3140110100411 is an equidigital number, since it uses as much as digits as its factorization.

3140110100411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 316457580.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 3140110100411 its reverse (1140010110413), we get a palindrome (4280120210824).

The spelling of 3140110100411 in words is "three trillion, one hundred forty billion, one hundred ten million, one hundred thousand, four hundred eleven".

Divisors: 1 9923 316447657 3140110100411