Base | Representation |
---|---|
bin | 1001001000111110001… |
… | …01011110001000110111 |
3 | 1010000121222021100002021 |
4 | 10210133011132020313 |
5 | 20121140324443341 |
6 | 400135142054011 |
7 | 31455361101661 |
oct | 4443705361067 |
9 | 1100558240067 |
10 | 314054140471 |
11 | 11120a414025 |
12 | 50a4811a307 |
13 | 237cc715666 |
14 | 112b38ad531 |
15 | 82814389d1 |
hex | 491f15e237 |
314054140471 has 2 divisors, whose sum is σ = 314054140472. Its totient is φ = 314054140470.
The previous prime is 314054140429. The next prime is 314054140489. The reversal of 314054140471 is 174041450413.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 314054140471 - 211 = 314054138423 is a prime.
It is a super-3 number, since 3×3140541404713 (a number of 35 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (314054140171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157027070235 + 157027070236.
It is an arithmetic number, because the mean of its divisors is an integer number (157027070236).
Almost surely, 2314054140471 is an apocalyptic number.
314054140471 is a deficient number, since it is larger than the sum of its proper divisors (1).
314054140471 is an equidigital number, since it uses as much as digits as its factorization.
314054140471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26880, while the sum is 34.
Adding to 314054140471 its reverse (174041450413), we get a palindrome (488095590884).
The spelling of 314054140471 in words is "three hundred fourteen billion, fifty-four million, one hundred forty thousand, four hundred seventy-one".
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