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314080854251 is a prime number
BaseRepresentation
bin1001001001000001010…
…11011000000011101011
31010000200211112112111112
410210200223120003223
520121214144314001
6400141534420535
731456134132503
oct4444053300353
91100624475445
10314080854251
111112234aa52a
1250a5506174b
1323805109928
14112b7264a03
158283963cbb
hex4920ad80eb

314080854251 has 2 divisors, whose sum is σ = 314080854252. Its totient is φ = 314080854250.

The previous prime is 314080854221. The next prime is 314080854253. The reversal of 314080854251 is 152458080413.

It is a strong prime.

It is an emirp because it is prime and its reverse (152458080413) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-314080854251 is a prime.

Together with 314080854253, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 314080854199 and 314080854208.

It is not a weakly prime, because it can be changed into another prime (314080854253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157040427125 + 157040427126.

It is an arithmetic number, because the mean of its divisors is an integer number (157040427126).

Almost surely, 2314080854251 is an apocalyptic number.

314080854251 is a deficient number, since it is larger than the sum of its proper divisors (1).

314080854251 is an equidigital number, since it uses as much as digits as its factorization.

314080854251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 153600, while the sum is 41.

The spelling of 314080854251 in words is "three hundred fourteen billion, eighty million, eight hundred fifty-four thousand, two hundred fifty-one".