Base | Representation |
---|---|
bin | 1001001001000101001… |
… | …10100001001011000100 |
3 | 1010000210002021120202221 |
4 | 10210202212201023010 |
5 | 20121300430312200 |
6 | 400145050342124 |
7 | 31460005411366 |
oct | 4444246411304 |
9 | 1100702246687 |
10 | 314113135300 |
11 | 11123a748788 |
12 | 50a63a2a944 |
13 | 2380b9ccc43 |
14 | 112bb668d36 |
15 | 82866dd91a |
hex | 49229a12c4 |
314113135300 has 18 divisors (see below), whose sum is σ = 681625503818. Its totient is φ = 125645254080.
The previous prime is 314113135279. The next prime is 314113135309. The reversal of 314113135300 is 3531311413.
It can be written as a sum of positive squares in 3 ways, for example, as 45598477444 + 268514657856 = 213538^2 + 518184^2 .
It is a super-2 number, since 2×3141131353002 (a number of 24 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is not an unprimeable number, because it can be changed into a prime (314113135309) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1570565577 + ... + 1570565776.
Almost surely, 2314113135300 is an apocalyptic number.
It is an amenable number.
314113135300 is an abundant number, since it is smaller than the sum of its proper divisors (367512368518).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
314113135300 is a wasteful number, since it uses less digits than its factorization.
314113135300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3141131367 (or 3141131360 counting only the distinct ones).
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 314113135300 its reverse (3531311413), we get a palindrome (317644446713).
The spelling of 314113135300 in words is "three hundred fourteen billion, one hundred thirteen million, one hundred thirty-five thousand, three hundred".
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