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3141301213003 is a prime number
BaseRepresentation
bin101101101101100100001…
…001001001011101001011
3102010022020200102121212111
4231231210021021131023
5402431341102304003
610403032134523151
7442644241515232
oct55554411113513
912108220377774
103141301213003
111001244706468
1242897b5064b7
1319a2b9b63005
14ac07b27db19
1556aa47e4e6d
hex2db6424974b

3141301213003 has 2 divisors, whose sum is σ = 3141301213004. Its totient is φ = 3141301213002.

The previous prime is 3141301212997. The next prime is 3141301213009. The reversal of 3141301213003 is 3003121031413.

3141301213003 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (3141301212997) and next prime (3141301213009).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3141301213003 is a prime.

It is a super-3 number, since 3×31413012130033 (a number of 38 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (3141301213009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1570650606501 + 1570650606502.

It is an arithmetic number, because the mean of its divisors is an integer number (1570650606502).

Almost surely, 23141301213003 is an apocalyptic number.

3141301213003 is a deficient number, since it is larger than the sum of its proper divisors (1).

3141301213003 is an equidigital number, since it uses as much as digits as its factorization.

3141301213003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 3141301213003 its reverse (3003121031413), we get a palindrome (6144422244416).

The spelling of 3141301213003 in words is "three trillion, one hundred forty-one billion, three hundred one million, two hundred thirteen thousand, three".