Search a number
-
+
314133003035 = 562826600607
BaseRepresentation
bin1001001001000111100…
…10010011101100011011
31010000211110122222011222
410210203302103230123
520121321022044120
6400151040242255
731460336316665
oct4444362235433
91100743588158
10314133003035
1111124a9886a5
1250a6a61038b
1323812b680b7
14112c015b535
158288315525
hex4923c93b1b

314133003035 has 4 divisors (see below), whose sum is σ = 376959603648. Its totient is φ = 251306402424.

The previous prime is 314133003013. The next prime is 314133003059. The reversal of 314133003035 is 530300331413.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 314133003035 - 222 = 314128808731 is a prime.

It is a super-2 number, since 2×3141330030352 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 314133002995 and 314133003013.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31413300299 + ... + 31413300308.

It is an arithmetic number, because the mean of its divisors is an integer number (94239900912).

Almost surely, 2314133003035 is an apocalyptic number.

314133003035 is a deficient number, since it is larger than the sum of its proper divisors (62826600613).

314133003035 is an equidigital number, since it uses as much as digits as its factorization.

314133003035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62826600612.

The product of its (nonzero) digits is 4860, while the sum is 26.

Adding to 314133003035 its reverse (530300331413), we get a palindrome (844433334448).

The spelling of 314133003035 in words is "three hundred fourteen billion, one hundred thirty-three million, three thousand, thirty-five".

Divisors: 1 5 62826600607 314133003035