Base | Representation |
---|---|
bin | 101101101101101010010… |
… | …001101001011010011111 |
3 | 102010022111212001001021011 |
4 | 231231222101221122133 |
5 | 402432043422314401 |
6 | 10403050252120051 |
7 | 442646631212062 |
oct | 55555221513237 |
9 | 12108455031234 |
10 | 3141404104351 |
11 | 10012977a2237 |
12 | 4289a9a66027 |
13 | 19a305279876 |
14 | ac08abc48d9 |
15 | 56aad86b451 |
hex | 2db6a46969f |
3141404104351 has 4 divisors (see below), whose sum is σ = 3141456270400. Its totient is φ = 3141351938304.
The previous prime is 3141404104303. The next prime is 3141404104367. The reversal of 3141404104351 is 1534014041413.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3141404104351 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3141404108351) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25992591 + ... + 26113168.
It is an arithmetic number, because the mean of its divisors is an integer number (785364067600).
Almost surely, 23141404104351 is an apocalyptic number.
3141404104351 is a deficient number, since it is larger than the sum of its proper divisors (52166049).
3141404104351 is an equidigital number, since it uses as much as digits as its factorization.
3141404104351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52166048.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 3141404104351 its reverse (1534014041413), we get a palindrome (4675418145764).
The spelling of 3141404104351 in words is "three trillion, one hundred forty-one billion, four hundred four million, one hundred four thousand, three hundred fifty-one".
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