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31415081497 is a prime number
BaseRepresentation
bin11101010000011111…
…000001101000011001
310000002101000111020221
4131100133001220121
51003314230101442
622233142120041
72161331533612
oct352037015031
9100071014227
1031415081497
1112360aa3778
126108a20021
132c685c4327
141740364c09
15c3ce9c467
hex7507c1a19

31415081497 has 2 divisors, whose sum is σ = 31415081498. Its totient is φ = 31415081496.

The previous prime is 31415081491. The next prime is 31415081519. The reversal of 31415081497 is 79418051413.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 29684188681 + 1730892816 = 172291^2 + 41604^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31415081497 is a prime.

It is a super-2 number, since 2×314150814972 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (31415081491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15707540748 + 15707540749.

It is an arithmetic number, because the mean of its divisors is an integer number (15707540749).

Almost surely, 231415081497 is an apocalyptic number.

It is an amenable number.

31415081497 is a deficient number, since it is larger than the sum of its proper divisors (1).

31415081497 is an equidigital number, since it uses as much as digits as its factorization.

31415081497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120960, while the sum is 43.

The spelling of 31415081497 in words is "thirty-one billion, four hundred fifteen million, eighty-one thousand, four hundred ninety-seven".