Base | Representation |
---|---|
bin | 1110010010100110011110… |
… | …00001100111000101110011 |
3 | 11010021020120220221221101002 |
4 | 13021103033001213011303 |
5 | 13104333312213343012 |
6 | 150500353154232215 |
7 | 6422262022010516 |
oct | 711231701470563 |
9 | 133236526857332 |
10 | 31425454043507 |
11 | a016507602a37 |
12 | 3636568b8566b |
13 | 146c53b663914 |
14 | 7a9000370d7d |
15 | 3976ac8e77c2 |
hex | 1c94cf067173 |
31425454043507 has 2 divisors, whose sum is σ = 31425454043508. Its totient is φ = 31425454043506.
The previous prime is 31425454043479. The next prime is 31425454043561. The reversal of 31425454043507 is 70534045452413.
It is a weak prime.
It is an emirp because it is prime and its reverse (70534045452413) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31425454043507 - 212 = 31425454039411 is a prime.
It is not a weakly prime, because it can be changed into another prime (31425454043407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15712727021753 + 15712727021754.
It is an arithmetic number, because the mean of its divisors is an integer number (15712727021754).
Almost surely, 231425454043507 is an apocalyptic number.
31425454043507 is a deficient number, since it is larger than the sum of its proper divisors (1).
31425454043507 is an equidigital number, since it uses as much as digits as its factorization.
31425454043507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032000, while the sum is 47.
The spelling of 31425454043507 in words is "thirty-one trillion, four hundred twenty-five billion, four hundred fifty-four million, forty-three thousand, five hundred seven".
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