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31430113441 = 49164012451
BaseRepresentation
bin11101010001011000…
…010111100010100001
310000010102022012012121
4131101120113202201
51003332102112231
622234440224241
72161603361536
oct352130274241
9100112265177
1031430113441
1112369530471
126111a6b081
132c6b75837c
141742358d8d
15c3e46b311
hex7516178a1

31430113441 has 4 divisors (see below), whose sum is σ = 31494126384. Its totient is φ = 31366100500.

The previous prime is 31430113439. The next prime is 31430113447. The reversal of 31430113441 is 14431103413.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31430113441 - 21 = 31430113439 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31430113447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32005735 + ... + 32006716.

It is an arithmetic number, because the mean of its divisors is an integer number (7873531596).

Almost surely, 231430113441 is an apocalyptic number.

It is an amenable number.

31430113441 is a deficient number, since it is larger than the sum of its proper divisors (64012943).

31430113441 is an equidigital number, since it uses as much as digits as its factorization.

31430113441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 64012942.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 31430113441 its reverse (14431103413), we get a palindrome (45861216854).

The spelling of 31430113441 in words is "thirty-one billion, four hundred thirty million, one hundred thirteen thousand, four hundred forty-one".

Divisors: 1 491 64012451 31430113441