Base | Representation |
---|---|
bin | 11101010001011100… |
… | …001011100110101100 |
3 | 10000010111011222112012 |
4 | 131101130023212230 |
5 | 1003332331110012 |
6 | 22234513500352 |
7 | 2161615024226 |
oct | 352134134654 |
9 | 100114158465 |
10 | 31431113132 |
11 | 1236a053561 |
12 | 61122716b8 |
13 | 2c6ba183c3 |
14 | 1742539416 |
15 | c3e5b7622 |
hex | 75170b9ac |
31431113132 has 48 divisors (see below), whose sum is σ = 55842124800. Its totient is φ = 15478713792.
The previous prime is 31431113111. The next prime is 31431113149. The reversal of 31431113132 is 23131113413.
It is a junction number, because it is equal to n+sod(n) for n = 31431113098 and 31431113107.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 51780773 + ... + 51781379.
It is an arithmetic number, because the mean of its divisors is an integer number (1163377600).
Almost surely, 231431113132 is an apocalyptic number.
It is an amenable number.
31431113132 is a deficient number, since it is larger than the sum of its proper divisors (24411011668).
31431113132 is a wasteful number, since it uses less digits than its factorization.
31431113132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1350 (or 1348 counting only the distinct ones).
The product of its digits is 648, while the sum is 23.
Adding to 31431113132 its reverse (23131113413), we get a palindrome (54562226545).
The spelling of 31431113132 in words is "thirty-one billion, four hundred thirty-one million, one hundred thirteen thousand, one hundred thirty-two".
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