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31431312433 is a prime number
BaseRepresentation
bin11101010001011100…
…111100010000110001
310000010111120002220201
4131101130330100301
51003332403444213
622234522035201
72161616514253
oct352134742061
9100114502821
1031431312433
111236a17a274
126112348b01
132c6ba88031
14174258bcd3
15c3e6066dd
hex75173c431

31431312433 has 2 divisors, whose sum is σ = 31431312434. Its totient is φ = 31431312432.

The previous prime is 31431312389. The next prime is 31431312541. The reversal of 31431312433 is 33421313413.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 21981917169 + 9449395264 = 148263^2 + 97208^2 .

It is a cyclic number.

It is not a de Polignac number, because 31431312433 - 221 = 31429215281 is a prime.

It is not a weakly prime, because it can be changed into another prime (31431312833) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15715656216 + 15715656217.

It is an arithmetic number, because the mean of its divisors is an integer number (15715656217).

Almost surely, 231431312433 is an apocalyptic number.

It is an amenable number.

31431312433 is a deficient number, since it is larger than the sum of its proper divisors (1).

31431312433 is an equidigital number, since it uses as much as digits as its factorization.

31431312433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7776, while the sum is 28.

Adding to 31431312433 its reverse (33421313413), we get a palindrome (64852625846).

The spelling of 31431312433 in words is "thirty-one billion, four hundred thirty-one million, three hundred twelve thousand, four hundred thirty-three".