314330433314133 has 4 divisors (see below), whose sum is σ = 419107244418848. Its totient is φ = 209553622209420.

The previous prime is 314330433314129. The next prime is 314330433314189. The reversal of 314330433314133 is 331413334033413.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 314330433314133 - 2² = 314330433314129 is a prime.

It is a super-2 number, since 2×314330433314133² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 314330433314091 and 314330433314100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (314330437314133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52388405552353 + ... + 52388405552358.

It is an arithmetic number, because the mean of its divisors is an integer number (104776811104712).

Almost surely, 2^{314330433314133} is an apocalyptic number.

It is an amenable number.

314330433314133 is a deficient number, since it is larger than the sum of its proper divisors (104776811104715).

314330433314133 is a wasteful number, since it uses less digits than its factorization.

314330433314133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 104776811104714.

The product of its (nonzero) digits is 419904, while the sum is 39.

Adding to 314330433314133 its reverse (331413334033413), we get a palindrome (645743767347546).

The spelling of 314330433314133 in words is "three hundred fourteen trillion, three hundred thirty billion, four hundred thirty-three million, three hundred fourteen thousand, one hundred thirty-three".