Base | Representation |
---|---|
bin | 1110010010110110111110… |
… | …11111000011100011010111 |
3 | 11010022002110211001220202111 |
4 | 13021123133133003203113 |
5 | 13110004441423213221 |
6 | 150504421033251451 |
7 | 6423024520351105 |
oct | 711333737034327 |
9 | 133262424056674 |
10 | 31434320132311 |
11 | a01a247250758 |
12 | 3638222263b87 |
13 | 1470322459105 |
14 | 7a9601a88c75 |
15 | 397a2ae71be1 |
hex | 1c96df7c38d7 |
31434320132311 has 2 divisors, whose sum is σ = 31434320132312. Its totient is φ = 31434320132310.
The previous prime is 31434320132249. The next prime is 31434320132317. The reversal of 31434320132311 is 11323102343413.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31434320132311 - 215 = 31434320099543 is a prime.
It is a super-2 number, since 2×314343201323112 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31434320132317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15717160066155 + 15717160066156.
It is an arithmetic number, because the mean of its divisors is an integer number (15717160066156).
Almost surely, 231434320132311 is an apocalyptic number.
31434320132311 is a deficient number, since it is larger than the sum of its proper divisors (1).
31434320132311 is an equidigital number, since it uses as much as digits as its factorization.
31434320132311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 31434320132311 its reverse (11323102343413), we get a palindrome (42757422475724).
The spelling of 31434320132311 in words is "thirty-one trillion, four hundred thirty-four billion, three hundred twenty million, one hundred thirty-two thousand, three hundred eleven".
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