Base | Representation |
---|---|
bin | 101101101111101011100… |
… | …000011110111001010101 |
3 | 102010112002221210110211212 |
4 | 231233223200132321111 |
5 | 403001013444114133 |
6 | 10404045343111205 |
7 | 443054436165662 |
oct | 55575340367125 |
9 | 12115087713755 |
10 | 3143572254293 |
11 | 10021aa648399 |
12 | 4292b3ba2505 |
13 | 19a58c509123 |
14 | ac214b30a69 |
15 | 56b88d96148 |
hex | 2dbeb81ee55 |
3143572254293 has 2 divisors, whose sum is σ = 3143572254294. Its totient is φ = 3143572254292.
The previous prime is 3143572254253. The next prime is 3143572254341. The reversal of 3143572254293 is 3924522753413.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1607616054724 + 1535956199569 = 1267918^2 + 1239337^2 .
It is a cyclic number.
It is not a de Polignac number, because 3143572254293 - 220 = 3143571205717 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3143572254203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1571786127146 + 1571786127147.
It is an arithmetic number, because the mean of its divisors is an integer number (1571786127147).
Almost surely, 23143572254293 is an apocalyptic number.
It is an amenable number.
3143572254293 is a deficient number, since it is larger than the sum of its proper divisors (1).
3143572254293 is an equidigital number, since it uses as much as digits as its factorization.
3143572254293 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5443200, while the sum is 50.
The spelling of 3143572254293 in words is "three trillion, one hundred forty-three billion, five hundred seventy-two million, two hundred fifty-four thousand, two hundred ninety-three".
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