Base | Representation |
---|---|
bin | 101101110000000110011… |
… | …111010011011101011111 |
3 | 102010120021111120210101002 |
4 | 231300012133103131133 |
5 | 403002430340231033 |
6 | 10404202313340515 |
7 | 443101603651436 |
oct | 55600637233537 |
9 | 12116244523332 |
10 | 3144024930143 |
11 | 1002412121469 |
12 | 4293bb70773b |
13 | 19a632231a66 |
14 | ac258cc811d |
15 | 56bb39b23e8 |
hex | 2dc067d375f |
3144024930143 has 2 divisors, whose sum is σ = 3144024930144. Its totient is φ = 3144024930142.
The previous prime is 3144024930041. The next prime is 3144024930149. The reversal of 3144024930143 is 3410394204413.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3144024930143 - 210 = 3144024929119 is a prime.
It is a super-2 number, since 2×31440249301432 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3144024930097 and 3144024930106.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3144024930149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1572012465071 + 1572012465072.
It is an arithmetic number, because the mean of its divisors is an integer number (1572012465072).
Almost surely, 23144024930143 is an apocalyptic number.
3144024930143 is a deficient number, since it is larger than the sum of its proper divisors (1).
3144024930143 is an equidigital number, since it uses as much as digits as its factorization.
3144024930143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 124416, while the sum is 38.
The spelling of 3144024930143 in words is "three trillion, one hundred forty-four billion, twenty-four million, nine hundred thirty thousand, one hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.086 sec. • engine limits •