Base | Representation |
---|---|
bin | 1110010011000100001111… |
… | …00000110100011000011010 |
3 | 11010022202211121022122112002 |
4 | 13021202013200310120122 |
5 | 13110114024114242132 |
6 | 150511555003121002 |
7 | 6423366022356662 |
oct | 711420740643032 |
9 | 133282747278462 |
10 | 31441434134042 |
11 | a02226798a529 |
12 | 3639688813162 |
13 | 1470bb72689aa |
14 | 7a9ab87dd1a2 |
15 | 397ce57a9262 |
hex | 1c988783461a |
31441434134042 has 4 divisors (see below), whose sum is σ = 47162151201066. Its totient is φ = 15720717067020.
The previous prime is 31441434133969. The next prime is 31441434134053. The reversal of 31441434134042 is 24043143414413.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 28941591708121 + 2499842425921 = 5379739^2 + 1581089^2 .
It is a junction number, because it is equal to n+sod(n) for n = 31441434133987 and 31441434134005.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7860358533509 + ... + 7860358533512.
Almost surely, 231441434134042 is an apocalyptic number.
31441434134042 is a deficient number, since it is larger than the sum of its proper divisors (15720717067024).
31441434134042 is a wasteful number, since it uses less digits than its factorization.
31441434134042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15720717067023.
The product of its (nonzero) digits is 221184, while the sum is 38.
Adding to 31441434134042 its reverse (24043143414413), we get a palindrome (55484577548455).
The spelling of 31441434134042 in words is "thirty-one trillion, four hundred forty-one billion, four hundred thirty-four million, one hundred thirty-four thousand, forty-two".
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