Base | Representation |
---|---|
bin | 101101110000010010010… |
… | …000101011000101010011 |
3 | 102010120210021012101100112 |
4 | 231300102100223011103 |
5 | 403003331414440311 |
6 | 10404234050311535 |
7 | 443106522416465 |
oct | 55602220530523 |
9 | 12116707171315 |
10 | 3144222421331 |
11 | 1002503650522 |
12 | 4294558885ab |
13 | 19a66411b154 |
14 | ac277216135 |
15 | 56bc5ec328b |
hex | 2dc1242b153 |
3144222421331 has 2 divisors, whose sum is σ = 3144222421332. Its totient is φ = 3144222421330.
The previous prime is 3144222421297. The next prime is 3144222421369. The reversal of 3144222421331 is 1331242224413.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (1331242224413) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3144222421331 - 234 = 3127042552147 is a prime.
It is a super-3 number, since 3×31442224213313 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (3144222421931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1572111210665 + 1572111210666.
It is an arithmetic number, because the mean of its divisors is an integer number (1572111210666).
Almost surely, 23144222421331 is an apocalyptic number.
3144222421331 is a deficient number, since it is larger than the sum of its proper divisors (1).
3144222421331 is an equidigital number, since it uses as much as digits as its factorization.
3144222421331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 27648, while the sum is 32.
Adding to 3144222421331 its reverse (1331242224413), we get a palindrome (4475464645744).
The spelling of 3144222421331 in words is "three trillion, one hundred forty-four billion, two hundred twenty-two million, four hundred twenty-one thousand, three hundred thirty-one".
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