Base | Representation |
---|---|
bin | 101101110000010011100… |
… | …111010110011101111111 |
3 | 102010120211211221210012111 |
4 | 231300103213112131333 |
5 | 403003403224042143 |
6 | 10404240221314451 |
7 | 443110216513606 |
oct | 55602347263577 |
9 | 12116754853174 |
10 | 3144245143423 |
11 | 100251545aa0a |
12 | 429461405a27 |
13 | 19a668a45587 |
14 | ac27a24ca3d |
15 | 56bc7eb099d |
hex | 2dc139d677f |
3144245143423 has 4 divisors (see below), whose sum is σ = 3144349602280. Its totient is φ = 3144140684568.
The previous prime is 3144245143399. The next prime is 3144245143463. The reversal of 3144245143423 is 3243415424413.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3144245143423 - 217 = 3144245012351 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3144245143463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52184265 + ... + 52244482.
It is an arithmetic number, because the mean of its divisors is an integer number (786087400570).
Almost surely, 23144245143423 is an apocalyptic number.
3144245143423 is a deficient number, since it is larger than the sum of its proper divisors (104458857).
3144245143423 is a wasteful number, since it uses less digits than its factorization.
3144245143423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 104458856.
The product of its digits is 552960, while the sum is 40.
The spelling of 3144245143423 in words is "three trillion, one hundred forty-four billion, two hundred forty-five million, one hundred forty-three thousand, four hundred twenty-three".
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