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314432100121 is a prime number
BaseRepresentation
bin1001001001101011001…
…11010001011100011001
31010001121022110200020211
410210311213101130121
520122424104200441
6400240443051121
731500630516106
oct4446547213431
91101538420224
10314432100121
111113937a5777
1250b32810aa1
132385cb0ac19
141130bb77aad
1582a46e6a81
hex49359d1719

314432100121 has 2 divisors, whose sum is σ = 314432100122. Its totient is φ = 314432100120.

The previous prime is 314432100091. The next prime is 314432100127. The reversal of 314432100121 is 121001234413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 196054128400 + 118377971721 = 442780^2 + 344061^2 .

It is a cyclic number.

It is not a de Polignac number, because 314432100121 - 25 = 314432100089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 314432100092 and 314432100101.

It is not a weakly prime, because it can be changed into another prime (314432100127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157216050060 + 157216050061.

It is an arithmetic number, because the mean of its divisors is an integer number (157216050061).

Almost surely, 2314432100121 is an apocalyptic number.

It is an amenable number.

314432100121 is a deficient number, since it is larger than the sum of its proper divisors (1).

314432100121 is an equidigital number, since it uses as much as digits as its factorization.

314432100121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 314432100121 its reverse (121001234413), we get a palindrome (435433334534).

The spelling of 314432100121 in words is "three hundred fourteen billion, four hundred thirty-two million, one hundred thousand, one hundred twenty-one".