314432100127 has 2 divisors, whose sum is σ = 314432100128. Its totient is φ = 314432100126.

The previous prime is 314432100121. The next prime is 314432100137. The reversal of 314432100127 is 721001234413.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-314432100127 is a prime.

It is a super-2 number, since 2×314432100127² (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 314432100095 and 314432100104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (314432100121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157216050063 + 157216050064.

It is an arithmetic number, because the mean of its divisors is an integer number (157216050064).

Almost surely, 2^314432100127 is an apocalyptic number.

314432100127 is a deficient number, since it is larger than the sum of its proper divisors (1).

314432100127 is an equidigital number, since it uses as much as digits as its factorization.

314432100127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 28.

The spelling of 314432100127 in words is "three hundred fourteen billion, four hundred thirty-two million, one hundred thousand, one hundred twenty-seven".