Base | Representation |
---|---|
bin | 100011101111110011111001… |
… | …0101110100001010010010111 |
3 | 1112020022121222022010202202212 |
4 | 1013133213302232201102113 |
5 | 312203143003230212403 |
6 | 3032425045524024035 |
7 | 123142062616162253 |
oct | 10737476256412227 |
9 | 1466277868122685 |
10 | 314434333054103 |
11 | 912089407a5189 |
12 | 2b323591b3201b |
13 | 1065b051982812 |
14 | 57909bab61263 |
15 | 265425a3924d8 |
hex | 11df9f2ba1497 |
314434333054103 has 2 divisors, whose sum is σ = 314434333054104. Its totient is φ = 314434333054102.
The previous prime is 314434333054099. The next prime is 314434333054141. The reversal of 314434333054103 is 301450333434413.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 314434333054103 - 22 = 314434333054099 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (314434333059103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157217166527051 + 157217166527052.
It is an arithmetic number, because the mean of its divisors is an integer number (157217166527052).
Almost surely, 2314434333054103 is an apocalyptic number.
314434333054103 is a deficient number, since it is larger than the sum of its proper divisors (1).
314434333054103 is an equidigital number, since it uses as much as digits as its factorization.
314434333054103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 933120, while the sum is 41.
Adding to 314434333054103 its reverse (301450333434413), we get a palindrome (615884666488516).
The spelling of 314434333054103 in words is "three hundred fourteen trillion, four hundred thirty-four billion, three hundred thirty-three million, fifty-four thousand, one hundred three".
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