Base | Representation |
---|---|
bin | 101101110000011100111… |
… | …000001011110110011011 |
3 | 102010121020200101022202122 |
4 | 231300130320023312123 |
5 | 403004213020120243 |
6 | 10404303452251455 |
7 | 443114114456063 |
oct | 55603470136633 |
9 | 12117220338678 |
10 | 3144400551323 |
11 | 1002595156199 |
12 | 4294a5470b8b |
13 | 19a691cb8b05 |
14 | ac292b443a3 |
15 | 56bd695c668 |
hex | 2dc1ce0bd9b |
3144400551323 has 4 divisors (see below), whose sum is σ = 3144417956040. Its totient is φ = 3144383146608.
The previous prime is 3144400551307. The next prime is 3144400551349. The reversal of 3144400551323 is 3231550044413.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3144400551323 - 24 = 3144400551307 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3144400550323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8428490 + ... + 8793647.
It is an arithmetic number, because the mean of its divisors is an integer number (786104489010).
Almost surely, 23144400551323 is an apocalyptic number.
3144400551323 is a deficient number, since it is larger than the sum of its proper divisors (17404717).
3144400551323 is a wasteful number, since it uses less digits than its factorization.
3144400551323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17404716.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 3144400551323 its reverse (3231550044413), we get a palindrome (6375950595736).
The spelling of 3144400551323 in words is "three trillion, one hundred forty-four billion, four hundred million, five hundred fifty-one thousand, three hundred twenty-three".
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