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3144402551 = 6015231951
BaseRepresentation
bin1011101101101011…
…1100011001110111
322010010202012101202
42323122330121313
522414431340201
61240003243115
7140630660243
oct27332743167
98103665352
103144402551
111373a2a1a4
1273907949b
133b15a3734
1421b875423
151360b9c6b
hexbb6bc677

3144402551 has 4 divisors (see below), whose sum is σ = 3149635104. Its totient is φ = 3139170000.

The previous prime is 3144402493. The next prime is 3144402557. The reversal of 3144402551 is 1552044413.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3144402551 - 210 = 3144401527 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3144402557) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2615375 + ... + 2616576.

It is an arithmetic number, because the mean of its divisors is an integer number (787408776).

Almost surely, 23144402551 is an apocalyptic number.

3144402551 is a deficient number, since it is larger than the sum of its proper divisors (5232553).

3144402551 is an equidigital number, since it uses as much as digits as its factorization.

3144402551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5232552.

The product of its (nonzero) digits is 9600, while the sum is 29.

The square root of 3144402551 is about 56074.9725902742. The cubic root of 3144402551 is about 1465.0284099528.

Adding to 3144402551 its reverse (1552044413), we get a palindrome (4696446964).

The spelling of 3144402551 in words is "three billion, one hundred forty-four million, four hundred two thousand, five hundred fifty-one".

Divisors: 1 601 5231951 3144402551