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314440343140223 is a prime number
BaseRepresentation
bin100011101111110110101100…
…0111101001011011101111111
31112020100012111011011210000002
41013133231120331023131333
5312203242310320441343
63032431522141024515
7123142364555106236
oct10737553075133577
91466305434153002
10314440343140223
1191210445294903
122b32478a85513b
131065b79bb703b1
145790dcb037b1d
1526544acd1d8b8
hex11dfb58f4b77f

314440343140223 has 2 divisors, whose sum is σ = 314440343140224. Its totient is φ = 314440343140222.

The previous prime is 314440343140141. The next prime is 314440343140229. The reversal of 314440343140223 is 322041343044413.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 314440343140223 - 220 = 314440342091647 is a prime.

It is a super-3 number, since 3×3144403431402233 (a number of 44 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (314440343140229) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157220171570111 + 157220171570112.

It is an arithmetic number, because the mean of its divisors is an integer number (157220171570112).

Almost surely, 2314440343140223 is an apocalyptic number.

314440343140223 is a deficient number, since it is larger than the sum of its proper divisors (1).

314440343140223 is an equidigital number, since it uses as much as digits as its factorization.

314440343140223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 331776, while the sum is 38.

Adding to 314440343140223 its reverse (322041343044413), we get a palindrome (636481686184636).

The spelling of 314440343140223 in words is "three hundred fourteen trillion, four hundred forty billion, three hundred forty-three million, one hundred forty thousand, two hundred twenty-three".