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31444224103141 is a prime number
BaseRepresentation
bin1110010011001001011011…
…10011101101001011100101
311010100001001001010202121221
413021210231303231023211
513110140232332300031
6150513135505540341
76423525120616453
oct711445563551345
9133301031122557
1031444224103141
11a023469836613
12363a1270446b1
131471240293295
147a9ca11719d3
15397e0a6b1a11
hex1c992dced2e5

31444224103141 has 2 divisors, whose sum is σ = 31444224103142. Its totient is φ = 31444224103140.

The previous prime is 31444224103091. The next prime is 31444224103151. The reversal of 31444224103141 is 14130142244413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 26080734024900 + 5363490078241 = 5106930^2 + 2315921^2 .

It is a cyclic number.

It is not a de Polignac number, because 31444224103141 - 27 = 31444224103013 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31444224103097 and 31444224103106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31444224103151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15722112051570 + 15722112051571.

It is an arithmetic number, because the mean of its divisors is an integer number (15722112051571).

Almost surely, 231444224103141 is an apocalyptic number.

It is an amenable number.

31444224103141 is a deficient number, since it is larger than the sum of its proper divisors (1).

31444224103141 is an equidigital number, since it uses as much as digits as its factorization.

31444224103141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36864, while the sum is 34.

Adding to 31444224103141 its reverse (14130142244413), we get a palindrome (45574366347554).

The spelling of 31444224103141 in words is "thirty-one trillion, four hundred forty-four billion, two hundred twenty-four million, one hundred three thousand, one hundred forty-one".