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314444012459 is a prime number
BaseRepresentation
bin1001001001101100101…
…00101101101110101011
31010001122010212212220112
410210312110231232223
520122440131344314
6400241550244535
731501134002003
oct4446624555653
91101563785815
10314444012459
1111139a4a1685
1250b367b674b
132386241c045
141130d599003
1582a579b43e
hex493652dbab

314444012459 has 2 divisors, whose sum is σ = 314444012460. Its totient is φ = 314444012458.

The previous prime is 314444012383. The next prime is 314444012461. The reversal of 314444012459 is 954210444413.

It is a strong prime.

It is an emirp because it is prime and its reverse (954210444413) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 314444012459 - 28 = 314444012203 is a prime.

It is a super-3 number, since 3×3144440124593 (a number of 35 digits) contains 333 as substring.

Together with 314444012461, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (314444011459) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157222006229 + 157222006230.

It is an arithmetic number, because the mean of its divisors is an integer number (157222006230).

Almost surely, 2314444012459 is an apocalyptic number.

314444012459 is a deficient number, since it is larger than the sum of its proper divisors (1).

314444012459 is an equidigital number, since it uses as much as digits as its factorization.

314444012459 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 276480, while the sum is 41.

The spelling of 314444012459 in words is "three hundred fourteen billion, four hundred forty-four million, twelve thousand, four hundred fifty-nine".