Base | Representation |
---|---|
bin | 1001001001101100101… |
… | …00101101101110101011 |
3 | 1010001122010212212220112 |
4 | 10210312110231232223 |
5 | 20122440131344314 |
6 | 400241550244535 |
7 | 31501134002003 |
oct | 4446624555653 |
9 | 1101563785815 |
10 | 314444012459 |
11 | 11139a4a1685 |
12 | 50b367b674b |
13 | 2386241c045 |
14 | 1130d599003 |
15 | 82a579b43e |
hex | 493652dbab |
314444012459 has 2 divisors, whose sum is σ = 314444012460. Its totient is φ = 314444012458.
The previous prime is 314444012383. The next prime is 314444012461. The reversal of 314444012459 is 954210444413.
It is a strong prime.
It is an emirp because it is prime and its reverse (954210444413) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 314444012459 - 28 = 314444012203 is a prime.
It is a super-3 number, since 3×3144440124593 (a number of 35 digits) contains 333 as substring.
Together with 314444012461, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (314444011459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157222006229 + 157222006230.
It is an arithmetic number, because the mean of its divisors is an integer number (157222006230).
Almost surely, 2314444012459 is an apocalyptic number.
314444012459 is a deficient number, since it is larger than the sum of its proper divisors (1).
314444012459 is an equidigital number, since it uses as much as digits as its factorization.
314444012459 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 276480, while the sum is 41.
The spelling of 314444012459 in words is "three hundred fourteen billion, four hundred forty-four million, twelve thousand, four hundred fifty-nine".
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