Base | Representation |
---|---|
bin | 1110010011010110001111… |
… | …11101111001101101001000 |
3 | 11010100200210121120121120010 |
4 | 13021223013331321231020 |
5 | 13110243330442400230 |
6 | 150520234404431520 |
7 | 6424160466151026 |
oct | 711530775715510 |
9 | 133320717517503 |
10 | 31451105434440 |
11 | a0263800a867a |
12 | 363b5276a85a0 |
13 | 1471a98b1a253 |
14 | 7aa35503b716 |
15 | 3981ae8899b0 |
hex | 1c9ac7f79b48 |
31451105434440 has 256 divisors, whose sum is σ = 94925080293120. Its totient is φ = 8336358051840.
The previous prime is 31451105434429. The next prime is 31451105434513. The reversal of 31451105434440 is 4443450115413.
It is a super-3 number, since 3×314511054344403 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 22906849594 + ... + 22906850966.
It is an arithmetic number, because the mean of its divisors is an integer number (370801094895).
Almost surely, 231451105434440 is an apocalyptic number.
31451105434440 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
31451105434440 is an abundant number, since it is smaller than the sum of its proper divisors (63473974858680).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31451105434440 is a wasteful number, since it uses less digits than its factorization.
31451105434440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3152 (or 3148 counting only the distinct ones).
The product of its (nonzero) digits is 230400, while the sum is 39.
Adding to 31451105434440 its reverse (4443450115413), we get a palindrome (35894555549853).
The spelling of 31451105434440 in words is "thirty-one trillion, four hundred fifty-one billion, one hundred five million, four hundred thirty-four thousand, four hundred forty".
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