Base | Representation |
---|---|
bin | 11101010010110000… |
… | …011110010111000011 |
3 | 10000012000202121210121 |
4 | 131102300132113003 |
5 | 1003404010210201 |
6 | 22241023241111 |
7 | 2162303605564 |
oct | 352260362703 |
9 | 100160677717 |
10 | 31453210051 |
11 | 1238057627a |
12 | 6119749197 |
13 | 2c734840c3 |
14 | 174544c16b |
15 | c414ce9a1 |
hex | 752c1e5c3 |
31453210051 has 2 divisors, whose sum is σ = 31453210052. Its totient is φ = 31453210050.
The previous prime is 31453210007. The next prime is 31453210067. The reversal of 31453210051 is 15001235413.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31453210051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31453209998 and 31453210025.
It is not a weakly prime, because it can be changed into another prime (31453210001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15726605025 + 15726605026.
It is an arithmetic number, because the mean of its divisors is an integer number (15726605026).
Almost surely, 231453210051 is an apocalyptic number.
31453210051 is a deficient number, since it is larger than the sum of its proper divisors (1).
31453210051 is an equidigital number, since it uses as much as digits as its factorization.
31453210051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 31453210051 its reverse (15001235413), we get a palindrome (46454445464).
The spelling of 31453210051 in words is "thirty-one billion, four hundred fifty-three million, two hundred ten thousand, fifty-one".
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