Base | Representation |
---|---|
bin | 100011110001010100110110… |
… | …1101000010100001000100111 |
3 | 1112021001112102112120002120001 |
4 | 1013202221231220110020213 |
5 | 312220100422141031033 |
6 | 3033104443225522131 |
7 | 123163113535323124 |
oct | 10742515550241047 |
9 | 1467045375502501 |
10 | 314642553455143 |
11 | 91289180790351 |
12 | 2b357a02643347 |
13 | 10674886092c04 |
14 | 579aad08bd74b |
15 | 265989534ae7d |
hex | 11e2a6da14227 |
314642553455143 has 2 divisors, whose sum is σ = 314642553455144. Its totient is φ = 314642553455142.
The previous prime is 314642553455053. The next prime is 314642553455149. The reversal of 314642553455143 is 341554355246413.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 314642553455143 - 213 = 314642553446951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (314642553455149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157321276727571 + 157321276727572.
It is an arithmetic number, because the mean of its divisors is an integer number (157321276727572).
Almost surely, 2314642553455143 is an apocalyptic number.
314642553455143 is a deficient number, since it is larger than the sum of its proper divisors (1).
314642553455143 is an equidigital number, since it uses as much as digits as its factorization.
314642553455143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 51840000, while the sum is 55.
The spelling of 314642553455143 in words is "three hundred fourteen trillion, six hundred forty-two billion, five hundred fifty-three million, four hundred fifty-five thousand, one hundred forty-three".
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