Base | Representation |
---|---|
bin | 100011110001011000010101… |
… | …0010100001110101011111111 |
3 | 1112021002020200110222122011202 |
4 | 1013202300222110032223333 |
5 | 312220211212044113241 |
6 | 3033112115420210115 |
7 | 123163466446332506 |
oct | 10742605224165377 |
9 | 1467066613878152 |
10 | 314650014051071 |
11 | 9129135a028506 |
12 | 2b35934509993b |
13 | 106754a493570a |
14 | 579b1db69583d |
15 | 2659b802e7d9b |
hex | 11e2c2a50eaff |
314650014051071 has 2 divisors, whose sum is σ = 314650014051072. Its totient is φ = 314650014051070.
The previous prime is 314650014051047. The next prime is 314650014051157. The reversal of 314650014051071 is 170150410056413.
It is a weak prime.
It is an emirp because it is prime and its reverse (170150410056413) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-314650014051071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (314650014051041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157325007025535 + 157325007025536.
It is an arithmetic number, because the mean of its divisors is an integer number (157325007025536).
Almost surely, 2314650014051071 is an apocalyptic number.
314650014051071 is a deficient number, since it is larger than the sum of its proper divisors (1).
314650014051071 is an equidigital number, since it uses as much as digits as its factorization.
314650014051071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50400, while the sum is 38.
The spelling of 314650014051071 in words is "three hundred fourteen trillion, six hundred fifty billion, fourteen million, fifty-one thousand, seventy-one".
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