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314650014051071 is a prime number
BaseRepresentation
bin100011110001011000010101…
…0010100001110101011111111
31112021002020200110222122011202
41013202300222110032223333
5312220211212044113241
63033112115420210115
7123163466446332506
oct10742605224165377
91467066613878152
10314650014051071
119129135a028506
122b35934509993b
13106754a493570a
14579b1db69583d
152659b802e7d9b
hex11e2c2a50eaff

314650014051071 has 2 divisors, whose sum is σ = 314650014051072. Its totient is φ = 314650014051070.

The previous prime is 314650014051047. The next prime is 314650014051157. The reversal of 314650014051071 is 170150410056413.

It is a weak prime.

It is an emirp because it is prime and its reverse (170150410056413) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-314650014051071 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (314650014051041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157325007025535 + 157325007025536.

It is an arithmetic number, because the mean of its divisors is an integer number (157325007025536).

Almost surely, 2314650014051071 is an apocalyptic number.

314650014051071 is a deficient number, since it is larger than the sum of its proper divisors (1).

314650014051071 is an equidigital number, since it uses as much as digits as its factorization.

314650014051071 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 50400, while the sum is 38.

The spelling of 314650014051071 in words is "three hundred fourteen trillion, six hundred fifty billion, fourteen million, fifty-one thousand, seventy-one".