Search a number
-
+
3147102215441 is a prime number
BaseRepresentation
bin101101110010111101111…
…010001101110100010001
3102010212012222001002012122
4231302331322031310101
5403030231131343231
610405431522304025
7443241061312622
oct55627572156421
912125188032178
103147102215441
111003751179458
12429b1a1b8015
1319aa02935b32
14ac46b88ba49
1556ce3c2077b
hex2dcbde8dd11

3147102215441 has 2 divisors, whose sum is σ = 3147102215442. Its totient is φ = 3147102215440.

The previous prime is 3147102215431. The next prime is 3147102215443. The reversal of 3147102215441 is 1445122017413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2054406222400 + 1092695993041 = 1433320^2 + 1045321^2 .

It is a cyclic number.

It is not a de Polignac number, because 3147102215441 - 218 = 3147101953297 is a prime.

It is a super-3 number, since 3×31471022154413 (a number of 38 digits) contains 333 as substring.

Together with 3147102215443, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (3147102215443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1573551107720 + 1573551107721.

It is an arithmetic number, because the mean of its divisors is an integer number (1573551107721).

Almost surely, 23147102215441 is an apocalyptic number.

It is an amenable number.

3147102215441 is a deficient number, since it is larger than the sum of its proper divisors (1).

3147102215441 is an equidigital number, since it uses as much as digits as its factorization.

3147102215441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26880, while the sum is 35.

The spelling of 3147102215441 in words is "three trillion, one hundred forty-seven billion, one hundred two million, two hundred fifteen thousand, four hundred forty-one".