Base | Representation |
---|---|
bin | 101101110011000000110… |
… | …000100001010111111011 |
3 | 102010212100021222002012021 |
4 | 231303000300201113323 |
5 | 403030330400141010 |
6 | 10405440350455311 |
7 | 443242211445160 |
oct | 55630060412773 |
9 | 12125307862167 |
10 | 3147150005755 |
11 | 100377614aa88 |
12 | 429b32204537 |
13 | 19aa0c7c9522 |
14 | ac473d6c067 |
15 | 56ce80108da |
hex | 2dcc0c215fb |
3147150005755 has 16 divisors (see below), whose sum is σ = 4370725509120. Its totient is φ = 2130728681952.
The previous prime is 3147150005723. The next prime is 3147150005771. The reversal of 3147150005755 is 5575000517413.
3147150005755 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 3147150005755 - 25 = 3147150005723 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 569102119 + ... + 569107648.
It is an arithmetic number, because the mean of its divisors is an integer number (273170344320).
Almost surely, 23147150005755 is an apocalyptic number.
3147150005755 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
3147150005755 is a deficient number, since it is larger than the sum of its proper divisors (1223575503365).
3147150005755 is a wasteful number, since it uses less digits than its factorization.
3147150005755 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1138209858.
The product of its (nonzero) digits is 367500, while the sum is 43.
The spelling of 3147150005755 in words is "three trillion, one hundred forty-seven billion, one hundred fifty million, five thousand, seven hundred fifty-five".
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