Base | Representation |
---|---|
bin | 1110010011111101100010… |
… | …11000101101001001011111 |
3 | 11010102201020211101210021202 |
4 | 13021332301120231021133 |
5 | 13111120032030441112 |
6 | 150534044004550115 |
7 | 6425535330115145 |
oct | 711766130551137 |
9 | 133381224353252 |
10 | 31472201421407 |
11 | a03431625094a |
12 | 36436346b233b |
13 | 1473a7b59c086 |
14 | 7ab396ad9595 |
15 | 3989e69476c2 |
hex | 1c9fb162d25f |
31472201421407 has 2 divisors, whose sum is σ = 31472201421408. Its totient is φ = 31472201421406.
The previous prime is 31472201421403. The next prime is 31472201421469. The reversal of 31472201421407 is 70412410227413.
It is a weak prime.
It is an emirp because it is prime and its reverse (70412410227413) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31472201421407 - 22 = 31472201421403 is a prime.
It is a super-2 number, since 2×314722014214072 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31472201421403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15736100710703 + 15736100710704.
It is an arithmetic number, because the mean of its divisors is an integer number (15736100710704).
Almost surely, 231472201421407 is an apocalyptic number.
31472201421407 is a deficient number, since it is larger than the sum of its proper divisors (1).
31472201421407 is an equidigital number, since it uses as much as digits as its factorization.
31472201421407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 75264, while the sum is 38.
The spelling of 31472201421407 in words is "thirty-one trillion, four hundred seventy-two billion, two hundred one million, four hundred twenty-one thousand, four hundred seven".
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