Base | Representation |
---|---|
bin | 101101110011100100001… |
… | …110011101100101111111 |
3 | 102010220212202122211020212 |
4 | 231303210032131211333 |
5 | 403033040213312101 |
6 | 10410015404503035 |
7 | 443263025343662 |
oct | 55634416354577 |
9 | 12126782584225 |
10 | 3147745057151 |
11 | 1003a510289a2 |
12 | 42a07954aa7b |
13 | 19aaa5b81846 |
14 | ac4ccdc76d9 |
15 | 56d303a21bb |
hex | 2dce439d97f |
3147745057151 has 2 divisors, whose sum is σ = 3147745057152. Its totient is φ = 3147745057150.
The previous prime is 3147745057117. The next prime is 3147745057283. The reversal of 3147745057151 is 1517505477413.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3147745057151 - 230 = 3146671315327 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3147745057151.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3147745057651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1573872528575 + 1573872528576.
It is an arithmetic number, because the mean of its divisors is an integer number (1573872528576).
Almost surely, 23147745057151 is an apocalyptic number.
3147745057151 is a deficient number, since it is larger than the sum of its proper divisors (1).
3147745057151 is an equidigital number, since it uses as much as digits as its factorization.
3147745057151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2058000, while the sum is 50.
The spelling of 3147745057151 in words is "three trillion, one hundred forty-seven billion, seven hundred forty-five million, fifty-seven thousand, one hundred fifty-one".
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