Base | Representation |
---|---|
bin | 100011110010101110110011… |
… | …1110111001001101010110111 |
3 | 1112021202000001100200222121111 |
4 | 1013211131213313021222313 |
5 | 312231232033413200323 |
6 | 3033333312054055451 |
7 | 123213062614540441 |
oct | 10745354767115267 |
9 | 1467660040628544 |
10 | 314835730209463 |
11 | 913530a0a53031 |
12 | 2b38933504a587 |
13 | 10689b608b48b8 |
14 | 57a61b86d5491 |
15 | 265e8ee76cc0d |
hex | 11e5767dc9ab7 |
314835730209463 has 2 divisors, whose sum is σ = 314835730209464. Its totient is φ = 314835730209462.
The previous prime is 314835730209397. The next prime is 314835730209541. The reversal of 314835730209463 is 364902037538413.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-314835730209463 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 314835730209398 and 314835730209407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (314835730209863) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157417865104731 + 157417865104732.
It is an arithmetic number, because the mean of its divisors is an integer number (157417865104732).
It is a 1-persistent number, because it is pandigital, but 2⋅314835730209463 = 629671460418926 is not.
Almost surely, 2314835730209463 is an apocalyptic number.
314835730209463 is a deficient number, since it is larger than the sum of its proper divisors (1).
314835730209463 is an equidigital number, since it uses as much as digits as its factorization.
314835730209463 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 39191040, while the sum is 58.
The spelling of 314835730209463 in words is "three hundred fourteen trillion, eight hundred thirty-five billion, seven hundred thirty million, two hundred nine thousand, four hundred sixty-three".
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