Base | Representation |
---|---|
bin | 1011101111000001… |
… | …0101101101000001 |
3 | 22010112022011000112 |
4 | 2323300111231001 |
5 | 22422400324301 |
6 | 1240323401105 |
7 | 141026440061 |
oct | 27360255501 |
9 | 8115264015 |
10 | 3150011201 |
11 | 1377110047 |
12 | 73ab23195 |
13 | 3b27b856c |
14 | 21c4d53a1 |
15 | 1368269bb |
hex | bbc15b41 |
3150011201 has 2 divisors, whose sum is σ = 3150011202. Its totient is φ = 3150011200.
The previous prime is 3150011177. The next prime is 3150011213. The reversal of 3150011201 is 1021100513.
3150011201 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2931681025 + 218330176 = 54145^2 + 14776^2 .
It is an emirp because it is prime and its reverse (1021100513) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3150011201 - 226 = 3082902337 is a prime.
It is not a weakly prime, because it can be changed into another prime (3150013201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1575005600 + 1575005601.
It is an arithmetic number, because the mean of its divisors is an integer number (1575005601).
Almost surely, 23150011201 is an apocalyptic number.
It is an amenable number.
3150011201 is a deficient number, since it is larger than the sum of its proper divisors (1).
3150011201 is an equidigital number, since it uses as much as digits as its factorization.
3150011201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30, while the sum is 14.
The square root of 3150011201 is about 56124.9605879594. The cubic root of 3150011201 is about 1465.8989463910.
Adding to 3150011201 its reverse (1021100513), we get a palindrome (4171111714).
The spelling of 3150011201 in words is "three billion, one hundred fifty million, eleven thousand, two hundred one".
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